Create variable names in loop python

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August undefined, 2024

WebAug 17, 2024 · I tried to create the loop in python. The code can be seen below. df=pd.DataFrame.copy (mef_list) form= ['','_M3','_M6','_M9','_M12','_LN','_C'] for i in range (0, len (form)): df=pd.DataFrame.copy (mef_list) df ['Variable_new']=df ['Variable']+str (form [i])

python - using for loops to create variables with different names ...

WebMay 28, 2024 · use NamedObject, that should work: apple='green' banana='yellow' orange='orange' fruits = [apple, banana, orange] apple = NamedObject ('apple', apple) print (apple) print (apple.name) this should print: green apple. If you dont understand, here is another similar thing: Access the name of a list in a Python print statement. Share. WebUse a dictionary instead of dynamically assigning variable names. Also, you can shorten the var3 and var4 lines using zip - see Is there a better way to iterate over two lists, getting one element from each list for each iteration?. At … optispex

How to create multiple class objects with a loop in python?

WebFeb 11, 2013 · I want to create a series of lists with unique names inside a for-loop and use the index to create the liste names. Here is what I want to do x = [100,2,300,4,75] for i in x: list_i=[] WebJan 20, 2016 · While using a list or dictionary is of course the right approach here, it is possible to create named variables, using exec (). You'll miss out on all the convenient operations that lists and dictionaries provide (think of len (), inserting, removing, sorting, and so on), but it's possible: WebOct 7, 2024 · Unless there is a strong reason to create multiple variables on the fly, it is normally in these situations to put things in a list of some sort, or a dictionary: mydict = {'var {}'.format (i):i for i in range (1,101)} Now access values with: mydict ["var1"] # returns 1 mydict.get ("var1") # returns 1 mydict.get ("var101") # returns None Share optispeed windows

python - Using a loop to create multiple variables - Stack Overflow

Create new data frame with the name from loop number

WebOct 6, 2024 · To create multiple variables you can use something like below, you use a for loop and store a pair of key-value, where key is the different variable names d= {} #empty dictionary for x in range (1,10): #for looping d ["string {0}".format (x)]="Variable1" The … WebApr 12, 2024 · PYTHON : How do you create different variable names while in a loop?To Access My Live Chat Page, On Google, Search for "hows tech developer connect"Here's a ... portofino homes turlock caWebApr 10, 2016 · All information is accessible in the current scope through meaningful variable names (i.e. first_names, last_names etc). If you put them in a list, you have to remember the first index is first_names, second is last_names, etc. These add another layer of confusion as your program/game code grows larger. optisport manus

"WebJul 18, 2024 · Then we name them x, y, and so on. The problem becomes more complicated when you need to declare variables dynamically in a loop. I came up with three ways to do this in Python. 1. Using the exec command. In the above program, I initially declared an empty dictionary and added the elements into the dictionary. " - Create variable names in loop python

Create variable names in loop python

generating variable names on fly in python - Stack Overflow

WebDec 16, 2011 · names = dict ( ("v" + str (i), i**2) for i in range (3)) print names ["v2"] # 4 And, for a fixed finite (and relatively small) set of variables, "unpacking" can also be used: v0, v1, v2 = [i**2 for i in range (3)] print v1 # 1 Share Improve this answer Follow edited Dec 16, 2011 at 7:22 answered Dec 16, 2011 at 7:00 user166390 Add a comment 4 WebJun 24, 2013 · I want to implement a loop where in each iteration I name the variable according to iterator value. For instance-for i in range(1,10): r = # some value Is there a way i can do it, other than making all these variables as string keys in a dictionary as mentioned in How do you create different variable names while in a loop? (Python ...

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WebJun 4, 2015 · Dynamically creating names in a Python namespace is almost invariably a bad idea. It would be much more sensible to use a dict d and write d [c] = pd.DataFrame (). Read this answer, for example, to start to understand why it's a bad idea. – holdenweb Jun 4, 2015 at 8:19 Show 1 more comment 6 Adding to the above great answers. WebSep 18, 2024 · Unless there is an overwhelming need to create a mess of variable names, I would just use a dictionary, where you can dynamically create the key names and associate a value to each. a = {} k = 0 while k < 10: # dynamically create key key = ... # calculate value value = ... a [key] = value k += 1

WebSo lets run through the loop together: Line 1: Python prints “Output:”. Line 2: So the first execution Python creates a generator that counts from 0 to 10. Python assigns the … WebDec 9, 2013 · I want this variable to have a unique name for each iteration of the loop( based on reclassInt items). Ideally this could create variables like line1, line2, ect to equal the string outputs from each iteration. Then I could string these together outside the loop to get my desired string. To be clear my end goal is this exact string:

WebThe problem is I want each review category to have its own variable, like a dataframe called "beauty_reviews", and another called "pet_reviews", containing the data read from reviews_beauty.json and reviews_pet.json respectively. WebIs there a way I can generate variable names in python in a loop and assign values to them? For example, if I have prices = [5, 12, 45] I want price1 = 5 price2 = 12 price3 = 45 Can I do this in a loop or something instead of manually assigning price1 = prices [0], price2 = prices [1] etc. Thank you. EDIT

WebYou can use variable key names to achieve the effect of variable variables without the security risk. >>> x = "spam" >>> z = {x: "eggs"} >>> z ["spam"] 'eggs' For cases where you're thinking of doing something like var1 = 'foo' var2 = 'bar' var3 = 'baz' ... a list may be more appropriate than a dict.

WebPYTHON : How do you create different variable names while in a loop?To Access My Live Chat Page, On Google, Search for "hows tech developer connect"Here's a ... optissimo worbWebHow to create new variables with names from list? This: name = ['mike', 'john', 'steve'] age = [20, 32, 19] index = 0 for e in name: name [index] = age [index] index = index+1 of … optisperse chemicalWebDec 16, 2024 · Python create variable according to for loop index - Stack Overflow Python create variable according to for loop index [duplicate] Ask Question Asked 5 years, 3 months ago Modified 5 years, 3 months ago Viewed 16k times -1 This question already has answers here: How can you dynamically create variables? [duplicate] (8 answers) optisport alexanderhof reserverenWebApr 4, 2024 · This tutorial will discuss different methods to create a dynamic variable name in Python. Use the for Loop to Create a Dynamic Variable Name in Python. The creation of a dynamic variable name in Python can be achieved with the help of iteration. Along with the for loop, the globals() function will also be used in this method. The globals ... optispire advance incWebJun 19, 2024 · create a List of data_frames as df = [] Now append your data_frames as for i in range (7): df.append (pd.read_csv (r'C:\Users\siddhn\Desktop\phone'+str (i)+'.csv', engine = 'python') You can then acess data_frames by indexing them like df [0] or df [1] ..... Share Improve this answer Follow answered Jun 19, 2024 at 5:02 pendela neelesh 13 6 portofino homes for sale with elevatorWebCreating a dictionary as it has mentioned, but in this case each key has the name of the object name that you want to create. Then the value is set as the class you want to instantiate, see for example: class MyClass: def __init__(self, name): self.name = name self.checkme = 'awesome {}'.format(self.name) ... optispiceWebNov 18, 2012 · I'm trying to create several arrays in a loop and have access to them further on. I don't understand why I can modify and print them within the loop but outside it says the variable doesn't exist. for i in range (0,3): a_i=[i] a_i.append(i+1) print a_i print a_1 portofino horsepower