WebThis process is called logarithmic derivative. Nothing really special, it's just the chain rule: the derivative of log f ( x) is f ′ ( x) f ( x) because the derivative of log x is 1 / x. Since you have f ( x) = x x + 1, you also have log f ( x) = ( x + 1) log x so, differentiating both sides, f ′ ( x) f ( x) = log x + ( x + 1) 1 x and you're done. Web\frac{d}{dx}(\frac{3x+9}{2-x}) \frac{d^2}{dx^2}(\frac{3x+9}{2-x}) (\sin^2(\theta))'' derivative\:of\:f(x)=3-4x^2,\:\:x=5; implicit\:derivative\:\frac{dy}{dx},\:(x-y)^2=x+y-1 …

Derivative Calculator: Wolfram Alpha

Webx^{2}-x-6=0-x+3\gt 2x+1; line\:(1,\:2),\:(3,\:1) f(x)=x^3; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120) \lim … WebBut ln (x) is a logarithmic function defined only for x-values greater than zero, while 1/x is a rational function defined for all non-zero x's. So would it be more accurate to say: the … how install j channel

Solve ln(x)+1/x^2 Microsoft Math Solver

WebBecause the derivative of ln (x) is 1/x, if we have the derivative of ln (u), where u is some polynomial, then we must use u-substitution, which says that d/dx [f (g (x))] = f' (g (x))*g' … WebFind the Derivative - d/dx y = natural log of x/(x+1) Step 1. Differentiate using the chain rule, which states that is where and . Tap for more steps... To apply the Chain Rule, set as . The derivative of with respect to is . Replace all occurrences of with . Step 2. Multiply by the reciprocal of the fraction to divide by . WebWhen the derivative of your expression for n it doesn't gives the expression for n+1. So it must be wrong ... – wece Mar 18, 2013 at 14:58 problem solved . thanks for the help guys – nicolas Mar 18, 2013 at 15:07 Add a comment 1 Answer Sorted by: 6 This is how I would do it f ( x) = ln ( 1 + x) f ′ ( x) = 1 x + 1 f ″ ( x) = − 1 ( x + 1) 2 high heels and knee pain